10x^2=108

Solution for 10x^2=108 equation:

10x^2=108

We move all terms to the left:

10x^2-(108)=0

a = 10; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·10·(-108)
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{30}}{2*10}=\frac{0-12\sqrt{30}}{20}
=-\frac{12\sqrt{30}}{20}
=-\frac{3\sqrt{30}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{30}}{2*10}=\frac{0+12\sqrt{30}}{20}
=\frac{12\sqrt{30}}{20}
=\frac{3\sqrt{30}}{5}
$